Get the register from the local map, and return its value if it has one.
2. Verify no errors in operation log, run health checks
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2026-03-03 17:00一年千亿，短剧生意比电影都大了？圈内师老师
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Increase the latency and send an update from both peers simultaneously. alice will accept bob’s update, but bob will reject alice’s. Since bob’s peer ID is greater, it breaks the timestamp tie.